June 17, 1998
1 (a) Basis Step: Let
. Then since
and
,
.
Hence
.
Inductive Step: Assume that
and
.
Then
and
. Hence
.
(b) Let
, and
. Then
.
But
.
Hence
does not hold in general.
2. Let L denote the given language. Also let
.
Then any pair of distinct strings
and
of S can be distinguished
with respect to L by
using
. Hence L is not regular.
3.
4 (a)
, R(3,2,1) = aa + b,
, and R(2,3,1) = a.
Hence
Hence