CS 281 Solution to Test II
1 (a) tex2html_wrap_inline101 tex2html_wrap_inline103 tex2html_wrap_inline105
(b) tex2html_wrap_inline107
= tex2html_wrap_inline109 = tex2html_wrap_inline111
= tex2html_wrap_inline113

2 (a)
(1) tex2html_wrap_inline117
(2) tex2html_wrap_inline121
(3) P
-------------
tex2html_wrap_inline127

(b) (4) tex2html_wrap_inline131 from (1) and Exportation
(5) tex2html_wrap_inline137 from (3) and (4)
(6) tex2html_wrap_inline127 from (2) and (5) with Hypothetical Syllogism.

3. Note that here we are trying to define tex2html_wrap_inline151 for every natural number n.

Basis Clause: tex2html_wrap_inline155 = tex2html_wrap_inline157
Inductive Clause: For every natural number n,
tex2html_wrap_inline161 = tex2html_wrap_inline163
Extremal Clause:

4. Basis Step: Prove tex2html_wrap_inline165 .

LHS = tex2html_wrap_inline169 , and RHS = tex2html_wrap_inline169 . Hence LHS = RHS.

Inductive Step: Prove tex2html_wrap_inline179 if tex2html_wrap_inline181 . .

tex2html_wrap_inline183
= tex2html_wrap_inline185
= tex2html_wrap_inline187
= tex2html_wrap_inline189 .




S. Toida
Thu May 29 11:16:56 EDT 1997